pathJoin

Abstract

Join two parts of a path according to the current platform

Description

Given a directory and a filename, or a base directory and a relative path, join these according to the current platform

Syntax

Sout pathJoin Spath1, Spath2

Arguments

Spath1: The first part to join
Spath2: The second part to join

Output

Sout: the result of joining both paths

Execution Time

Init

Examples

<CsoundSynthesizer>
<CsOptions>
--nosound
</CsOptions>

<CsInstruments>
sr     = 44100
ksmps  = 64
nchnls = 2
0dbfs  = 1

instr 1
    Sdir = "/home/bar"
    Sbase = "filename.ext"
    Spath = pathJoin(Sdir, Sbase)
    prints "Spath: \"%s\", Sdir: \"%s\", Sbase: \"%s\"\n", Spath, Sdir, Sbase

    Sdir = "/home/bar/"
    Sbase = "filename.ext"
    Spath = pathJoin(Sdir, Sbase)
    prints "Spath: \"%s\", Sdir: \"%s\", Sbase: \"%s\"\n", Spath, Sdir, Sbase

    Sdir = ""
    Sbase = "filename.ext"
    Spath = pathJoin(Sdir, Sbase)
    prints "Spath: \"%s\", Sdir: \"%s\", Sbase: \"%s\"\n", Spath, Sdir, Sbase

    Sdir = "/home/bar"
    Sbase = ""
    Spath = pathJoin(Sdir, Sbase)
    prints "Spath: \"%s\", Sdir: \"%s\", Sbase: \"%s\"\n", Spath, Sdir, Sbase

    turnoff
endin

</CsInstruments>

<CsScore>

i1 0 1
; f0 3600

</CsScore>
</CsoundSynthesizer>

Credits

Eduardo Moguillansky, 2020